Former England cricketer James Foster feels Joe Root has a very good chance to surpass legendary Sachin Tendulkar and become the leading Test run-scorer. Root has been on a sensational run for the past couple of years in the red-ball cricket. With the hunger and drive he has expressed to score runs, Root has caused a debate among fans and former cricketers about something that was believed to be untouched.
With another Test series riddled with runs, Root stands 2,949 runs away from levelling Sachin’s feat of highest run-tally of 15,921 in red-ball cricket. Former English cricketers have pondered the longevity of Root’s career and the possibility of surpassing Sachin’s impeccable tally.
Foster weighed in on the possibility of Root going past Sachin and admits he has a good shot at establishing himself as the leading run-scorer in the format.
Also Read: Mohammed Shami’s Net Worth REVEALED: Income, Cars And Endorsements – A Million-Dollar Journey
“Joe is a world-class player. Joe continues to keep evolving his game. He has played so much cricket, but he is still very hungry. He just loves it. Anyone with that ability and quality who still has the hunger to perform and play cricket. He has probably got a very good chance,” Foster told.
Joe Root’s Previous And Recent Records
Here’s a table summarizing Joe Root’s remarkable Test achievements:
| Record | Details |
|---|---|
| Runs in New Zealand (Test format) | 1006 runs |
| Leading Run-Scorer vs New Zealand | 1925 runs (surpassing Javed Miandad’s 1919) |
| Leading Run-Scorer vs India | 2846 runs |
| Leading Run-Scorer vs Pakistan | 2911 runs |
| Leading Run-Scorer vs Bangladesh | 1816 runs |
| Most Half-Centuries in New Zealand (by a visitor) | 8 half-centuries |
| Total Test Runs | 12,972 runs |
| Test Average | 50.87 |
| Centuries | 36 centuries |
| Half-Centuries | 65 fifties |
| Total Test Matches Played | 152 matches |
| First Touring Player to Score 1006 Runs in NZ | Yes (achieved the feat) |
Also Read: Smriti Mandhana’s Net Worth: How Much Does ‘RCB Skipper’ Earns?
